Example 1, shell external-pressure thickness
The shell external-pressure case governs. The calc solves UG-28 and CS-2 for 15 psi external pressure and arrives at a required corroded wall of 0.1145 in, then adds 0.125 in corrosion allowance for a design thickness of 0.2395 in.
t_required (external) = 0.1145 in
t_design = t_required + CA = 0.1145 + 0.125 = 0.2395 in
Example 2, shell internal-pressure thickness
Using Appendix 1-1 with outside-diameter form, the shell internal-pressure requirement at 150 psi and 250 °F is about 0.213 in corroded. Because 0.213 in is less than 0.2395 in, the external-pressure case remains controlling.
t_required (internal) ≈ 0.213 in
t_required (internal) < t_design (external) = 0.2395 in
Example 3, 2:1 SE head thickness
For the 20 in OD SA-516-70 heads, Appendix 1-4(c) gives a corroded internal-pressure thickness of 0.1987 in. The adopted minimum thickness after forming is 0.3125 in, so the formed head has margin over both internal and external pressure requirements.
t_required, head (internal) = 0.1987 in
t_min after forming = 0.3125 in
Example 4, 10 in nozzle reinforcement
The 10 NPS set-in nozzle with reinforcement pad passes UG-37 area replacement. The calc reports required reinforcement area of about 0.875 in² and available area of about 3.87 in², so the opening is adequately reinforced.
A_required ≈ 0.875 in²
A_available ≈ 3.87 in² > A_required